 Teacher resources and professional development across the curriculum

Teacher professional development and classroom resources across the curriculum            Solutions for Session 6, Part A

See solutions for Problems: A1 | A2 | A3    Problem A1

Draw a square with side lengths of 5 units around the given square so that the vertices of the given square are on the sides of the new square. The area of the new square is 25 square units (since its side length is 5), and its area is larger than the area of the original square by the area of the four right triangles whose legs have lengths of 2 and 3 units. So the area of the original square is 25 - 4 • (3 • 2 / 2) = 13 square units.

 It looks like this:  Another method is the following: Again, the area of the square is 4 • (2 • 3 / 2) + 1 • 1 = 13 square units.   Problem A2

Using the same method from A1, here are the areas:   Figure # Area of Square on Side a Area of Square on Side b Area of Square on Side c        Figure 1: 4 9 13 Figure 2: 1 4 5 Figure 3: 4 4 8    Problem A3 The area of the square on side c is always the sum of the areas of the squares on the other two sides.     