Teacher resources and professional development across the curriculum

Teacher professional development and classroom resources across the curriculum

Monthly Update sign up
Mailing List signup
Search
Follow The Annenberg Learner on LinkedIn Follow The Annenberg Learner on Facebook Follow Annenberg Learner on Twitter
MENU
Learning Math Home
Session 2 Solutions
 
Session 2 Part A Part B Part C Part D Part E Homework
 
Glossary
data Site Map
Session 2 Materials:
Notes
Solutions
 

B C D E
Homework

Video

Solutions for Session 2, Part D

See solutions for Problems: D1 | D2 | D3 | D4 | D5 | D6| D7


Problem D1

The median is in the ninth position, with 28 raisins.

<< back to Problem D1


 

Problem D2

You would find the median in the same way, by finding the value that has an equal number of values above and below it. You could still do this by removing the highest and lowest values in the data set until only the median remains.

<< back to Problem D2


 

Problem D3

The ordered list is 63, 68, 70, 70, 72, 72, 75, 82, 84. The value in the center of this list is 72, which makes it the median.

<< back to Problem D3


 

Problem D4

The median is the ninth number in the ordered list, which, in this case, is 6.

<< back to Problem D4


 

Problem D5

The second value is 26, since its position (2) is higher than the cumulative frequency of 25 (1), but not higher than the cumulative frequency of 26 (3).

<< back to Problem D5


 

Problem D6

They also have 27 raisins.

<< back to Problem D6


 

Problem D7

We know that the median is in the ninth position (of 17 total boxes), which falls between the cumulative frequency of 27 (6) and 28 (11); therefore, the median is 28.

<< back to Problem D7


 

Learning Math Home | Data Home | Register | Glossary | Map | ©

Session 2 | Notes | Solutions | Video

© Annenberg Foundation 2014. All rights reserved. Legal Policy